#include<bits/stdc++.h>
using namespace std;
int main(){
    int n,a[1000][1000];
    cin>>n;
    a[0][0]=1;
    for(int i=1;i<n;i++){
        a[i][0]=1;
        for(int j=1;j<n;j++){
            a[i][j] = a[i-1][j-1] + a[i-1][j];
        }
    }
    for(int i=0;i<n;i++){
        for(int j=0;j<n;j++){
            if(a[i][j]!=0)cout<<a[i][j]<<" ";
        }
        cout<<endl;
    }  
    return 0;
}

包对的

# 三行代码就能搞定

#include<bits/stdc++.h> 
using namespace std; 
int a[25][25];int main(){ios::sync_with_stdio(false); cin.tie(0); int n; cin >> n; a[1][1] = 1; for(int i = 2; i <= n; i++){ for(int j = 1; j <= i; j++){ a[i][j] = a[i-1][j-1] + a[i-1][j]; } } for(int i = 1; i <= n; i++){ for(int j = 1; j <= i; j++){ cout << a[i][j] << " "; } cout << "\n"; }return 0;}

#点个赞:)

#include<bits/stdc++.h> 
using namespace std; 
int a[25][25];
 int main(){ 
 	ios::sync_with_stdio(false); 
	cin.tie(0); 
 	int n; 
 	cin >> n; 
	a[1][1] = 1; 
 	for(int i = 2; i <= n; i++){ 
 		for(int j = 1; j <= i; j++){ 
 			a[i][j] = a[i-1][j-1] + a[i-1][j]; 
 		} 
 	} 
 	for(int i = 1; i <= n; i++){ 
 		for(int j = 1; j <= i; j++){ 
 			cout << a[i][j] << " "; 
 		} 
 		cout<<"\n";
  	}
  	return 0;
}

#include <vector>
using namespace std;
int main() {
    vector<long long> dp(71, 0);
    dp[0]=1;
    dp[1]=1;
    dp[2]=2;
    dp[3]=4;
    for(int i=4;i<=70;++i) {
        dp[i]=dp[i-1]+dp[i-2]+dp[i-3];
    }
    int n;
    while(cin>>n&&n!=0) {
        cout<<dp[n]<<endl;
    }
    return 0;
}

a[i][j] = a[i-1][j-1] + a[i-1][j]

#include <bits/stdc++.h> using namespace std; int main() { int a[25][25]={ }; int n; cin>>n; for(int i=1;i<=n;i++){ for(int j=1;j<=i;j++){ if(j1||ji){ a[i][j]=1; } } } for(int i=3;i<=n;i++){ for(int j=2;j<=i;j++){ a[i][j]=a[i-1][j]+a[i-1][j-1]; } } for(int i=1;i<=n;i++){ for(int j=1;j<=i;j++){ cout<<a[i][j]<<" "; }cout<<endl; } return 0; }

正版代码来了 #include<bits/stdc++.h> using namespace std; int a[25][25]; int main(){ ios::sync_with_stdio(false); cin.tie(0); int n; cin >> n; a[1][1] = 1; for(int i = 2; i <= n; i++){ for(int j = 1; j <= i; j++){ a[i][j] = a[i-1][j-1] + a[i-1][j]; } } for(int i = 1; i <= n; i++){ for(int j = 1; j <= i; j++){ cout << a[i][j] << " "; } cout << "\n"; }

return 0;

} 格式可能有点问题，请谅解